UsingSyslog: Difference between revisions

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==Calling syslog method from your C source code==
==Calling syslog method from your C source code==
This part is quiet simple, but we need to correctly use each parameter.
This part is quite simple, but we need to correctly use each parameter.
First step is to declare us as syslog client :
First step is to declare us as syslog client :
<source lang="C">
<source lang="C">

Revision as of 14:40, 21 September 2012

Calling syslog method from your C source code

This part is quite simple, but we need to correctly use each parameter. First step is to declare us as syslog client :

...
#include <syslog.h>

int main(int argc, char *argv[])
{
    ...
    openlog("program_name", LOG_PID, LOG_USER);
    ...
    closelog();
    ...
}

Then, you can call syslog from your code using printf like format :

    ...
    syslog(LOG_INFO, "%s called with %d arguments\n", argv[0], argc);
    ...

If you compile the source file:

// log_syslog.c
#include <syslog.h>

int main(int argc, char *argv[])
{
    openlog("program_name", LOG_PID, LOG_USER);
    syslog(LOG_INFO, "%s called with %d arguments", argv[0], argc - 1);
    closelog();
    return 0;
}

With the command :

itsme@mycomputer:~/log_syslog$ gcc log_syslog.c -o log-syslog

Then run it 2 times :

itsme@mycomputer:~/log_syslog$ ./log_syslog
itsme@mycomputer:~/log_syslog$ ./log_syslog pim pam poum

You will probably obtain no result in shell, but you can take a look in your system log (/var/log/syslog or /var/log/messages)

itsme@mycomputer:~/log_syslog$ tail -n 2 /var/log/syslog
Sep 19 18:46:49 mycomputer program_name[3022]: ./log_syslog called with 0 arguments
Sep 19 18:46:53 mycomputer program_name[3023]: ./log_syslog called with 3 arguments

We can notice, that the lines contain program_name[PID] pattern showing us the name we have specified in openlog and the pid of the process because we ask it with LOG_PID argument.